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Positions of 0 in A190236; complement of A190238.
3

%I #10 Dec 28 2017 03:39:59

%S 2,4,5,6,7,8,10,12,13,14,15,16,18,20,22,23,24,25,26,28,30,31,32,33,34,

%T 36,38,39,40,41,42,44,46,47,48,49,50,52,54,56,57,58,59,60,62,64,65,66,

%U 67,68,70,72,73,74,75,76,78,80,81,82,83,84,86,88,89,90,91,92,93,94,96,98,99,100,101,102,104,106,107,108,109,110,112,114,115,116

%N Positions of 0 in A190236; complement of A190238.

%H G. C. Greubel, <a href="/A190237/b190237.txt">Table of n, a(n) for n = 1..8000</a>

%t u = 1/2; v = GoldenRatio;

%t f[n_] := Floor[n*u + n*v] - Floor[n*u] - Floor[n*v]

%t t = Table[f[n], {n, 1, 120}] (* A190236 *)

%t Flatten[Position[t, 0]] (* A190237 *)

%t Flatten[Position[t, 1]] (* A190238 *)

%Y Cf. A190236, A190238.

%K nonn

%O 1,1

%A _Clark Kimberling_, May 06 2011