login
Positions of 0 in A190207; complement of A190209.
3

%I #10 Dec 28 2017 03:38:44

%S 8,11,14,16,19,22,24,25,27,28,30,31,32,33,35,36,38,39,40,41,42,45,53,

%T 56,59,61,62,64,67,69,70,72,73,75,76,77,78,79,80,81,83,84,90,93,98,

%U 101,104,106,107,109,110,112,114,115,117,118,120,121,122,123,124,125,126,127,135,138,141,143,146,149,151,152,154,155,157

%N Positions of 0 in A190207; complement of A190209.

%H G. C. Greubel, <a href="/A190208/b190208.txt">Table of n, a(n) for n = 1..5450</a>

%t u = 7^(1/2); v = 1/u;

%t f[n_] := Floor[n*u + n*v] - Floor[n*u] - Floor[n*v]

%t t = Table[f[n], {n, 1, 120}] (* A190207 *)

%t Flatten[Position[t, 0]] (* A190208 *)

%t Flatten[Position[t, 1]] (* A190209 *)

%Y Cf. A190207, A190209.

%K nonn

%O 1,1

%A _Clark Kimberling_, May 05 2011