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Pattern of the 97 consecutive leap years in a 400 year cycle of the Gregorian calendar.
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%I #12 Jul 14 2012 10:42:42

%S 0,4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,

%T 96,104,108,112,116,120,124,128,132,136,140,144,148,152,156,160,164,

%U 168,172,176,180,184,188,192,196,204,208,212,216,220,224,228,232,236,240,244,248,252,256,260,264,268,272,276,280,284,288,292,296,304,308,312,316,320,324,328,332,336,340,344,348,352,356,360,364,368,372,376,380,384,388,392,396

%N Pattern of the 97 consecutive leap years in a 400 year cycle of the Gregorian calendar.

%C For each year y divisible exactly by 400 the consecutive 97 leap years, in the 400 year cycle of the Gregorian calendar, are y+a(n), n=1,2,...,97.

%C A 4000 rule (declaring the years 4000,8000,... non-leap years) is not used here.

%C For the leap year rule for the Gregorian calendar see, e.g., Wikipedia.

%H <a href="/index/Ca#calendar">Index entries for sequences related to calendars</a>

%F Eliminate in the list 4*k, k=0,..99, the numbers 100, 200 and 300.

%e 1600 + a(n), n=1,...,97 are leap years,

%e 2000 + a(n), n=1,...,97 are leap years, etc.

%Y Cf. A131921.

%K nonn,easy,fini,full

%O 1,2

%A _Wolfdieter Lang_, May 02 2011