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Positions of 0 in A188371; complement of A188373.
3

%I #14 Apr 12 2018 02:45:27

%S 1,2,4,5,6,7,8,9,11,12,14,15,16,18,19,21,22,23,24,25,26,28,29,31,32,

%T 33,35,36,38,39,40,41,42,43,45,46,48,49,50,52,53,55,56,57,59,60,62,63,

%U 64,65,66,67,69,70,72,73,74,76,77,79,80,81,82,83,84,86,87,89,90,91,93,94,96,97,98,100,101,103,104,105,106,107,108,110,111,113,114,115,117,118,120,121,122,123

%N Positions of 0 in A188371; complement of A188373.

%C See A188014, A188371.

%H G. C. Greubel, <a href="/A188372/b188372.txt">Table of n, a(n) for n = 1..10000</a>

%t r=2^(-1/2); k=6;

%t t=Table[Floor[n*r]-Floor[(n-k)*r]-Floor[k*r],{n,1,220}] (*A188371*)

%t Flatten[Position[t,0]] (*A188372*)

%Y Cf. A188014, A188371, A188373.

%K nonn

%O 1,2

%A _Clark Kimberling_, Mar 29 2011

%E Typo in name corrected by _Michel Dekking_, Oct 01 2016