%I #4 Mar 30 2012 18:57:22
%S 0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,
%T 0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,
%U 0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,0,1,1,1,0,1,1,1,0,1,1,1
%N [nr+kr]-[nr]-[kr], where r=sqrt(5), k=3, [ ]=floor.
%C See A187950.
%F a(n)=[nr+3r]-[nr]-[3r], where r=sqrt(5).
%t r=5^(1/2); k=3;
%t seqA=Table[Floor[n*r+k*r]-Floor[n*r]-Floor[k*r], {n,1,220}] (* A188260 *)
%t Flatten[Position[seqA,0] ] (* A188261 *)
%t Flatten[Position[seqA,1] ] (* A188262 *)
%Y Cf. A187950, A188261, A188262.
%K nonn
%O 1
%A _Clark Kimberling_, Mar 25 2011
|