%I #4 Mar 30 2012 18:57:22
%S 1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,
%T 1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,
%U 1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1
%N [nr]-[kr]-[nr-kr], where r=sqrt(5), k=2, [ ]=floor.
%C See A188014.
%F a(n)=[nr]-[2r]-[nr-2r], where r=sqrt(5).
%t r=5^(1/2)); k=2;
%t t=Table[Floor[n*r]-Floor[(n-k)*r]-Floor[k*r],{n,1,220}] (*A188189*)
%t Flatten[Position[t,0]] (*A188190*)
%t Flatten[Position[t,1]] (*A188191*)
%Y Cf. A188014, A188190, A188191.
%K nonn
%O 1
%A _Clark Kimberling_, Mar 23 2011