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A188031 [nr]-[nr-kr]-[kr], where r=(1+sqrt(5))/2, k=11, [ ]=floor. 3

%I #4 Mar 30 2012 18:57:22

%S 1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,1,1,1,

%T 1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,1,1,1,

%U 1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,1,0

%N [nr]-[nr-kr]-[kr], where r=(1+sqrt(5))/2, k=11, [ ]=floor.

%C See A188014.

%F a(n)=[nr]-[nr-11r]-[11r], where r=(1+sqrt(5))/2.

%t r=(1+5^(1/2))/2; k=11;

%t t=Table[Floor[n*r]-Floor[(n-k)*r]-Floor[k*r],{n,1,220}] (*A188031*)

%t Flatten[Position[t,0]] (*A188032*)

%t Flatten[Position[t,1]] (*A188033*)

%Y Cf. A188014, A188032, A188033.

%K nonn

%O 1

%A _Clark Kimberling_, Mar 19 2011

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