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[nr]-[nr-kr]-[kr], where r=(1+sqrt(5))/2, k=7, [ ]=floor.
3

%I #4 Mar 30 2012 18:57:22

%S 0,1,0,0,1,0,0,0,0,1,0,0,1,0,1,0,0,1,0,0,0,0,1,0,0,1,0,1,0,0,1,0,0,1,

%T 0,1,0,0,1,0,0,0,0,1,0,0,1,0,1,0,0,1,0,0,0,0,1,0,0,1,0,1,0,0,1,0,0,1,

%U 0,1,0,0,1,0,0,0,0,1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,0,1,0,0,0,0,1,0,0,1,0,1,0,0,1,0,0,0,0,1,0,0,1,0,1

%N [nr]-[nr-kr]-[kr], where r=(1+sqrt(5))/2, k=7, [ ]=floor.

%C See A188014.

%F a(n)=[nr]-[nr-7r]-[7r], where r=(1+sqrt(5))/2.

%t r=(1+5^(1/2))/2; k=7;

%t t=Table[Floor[n*r]-Floor[(n-k)*r]-Floor[k*r],{n,1,220}] (*A188020*)

%t Flatten[Position[t,0]] (*A188024*)

%t Flatten[Position[t,1]] (*A188025*)

%Y Cf. A188014, A188024, A188025.

%K nonn

%O 1

%A _Clark Kimberling_, Mar 19 2011