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A187093
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a(0)=0, a(1)=a(2)=1; thereafter, a(n+1) = n^2 - a(n-1).
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3
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0, 1, 1, 3, 8, 13, 17, 23, 32, 41, 49, 59, 72, 85, 97, 111, 128, 145, 161, 179, 200, 221, 241, 263, 288, 313, 337, 363, 392, 421, 449, 479, 512, 545, 577, 611, 648, 685, 721, 759, 800, 841, 881, 923, 968, 1013, 1057, 1103, 1152, 1201, 1249, 1299, 1352, 1405, 1457
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OFFSET
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0,4
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COMMENTS
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The original definition was equivalent to: Let S(n) = sum_{i=0..n} a(i), then n^2+a(n)-S(n+1) = S(n-2). This in turn simplifies to the present definition.
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LINKS
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FORMULA
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a(n) = (n^2 - 1 + (-1)^floor(n/2) * A000034(n))/2.
G.f.: x*(-1+2*x+x^3-4*x^2) / ( (x^2+1)*(x-1)^3 ).
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MAPLE
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A000034 := proc(n) op(1+(n mod 2), [1, 2]) ; end proc:
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MATHEMATICA
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LinearRecurrence[{3, -4, 4, -3, 1}, {0, 1, 1, 3, 8}, 60] (* Jean-François Alcover, Mar 30 2020 *)
Join[{0}, RecurrenceTable[{a[1]==a[2]==1, a[n+1]==n^2-a[n-1]}, a, {n, 60}]] (* Harvey P. Dale, Jan 05 2023 *)
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PROG
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(Python)
print(0, end=', ') # a(-1)=0
prpr = prev = 1 # a(0)=a(1)=1
for n in range(2, 77):
print(prpr, end=', ')
curr = n*n - prpr # a(n) = n^2 - a(n-2)
prpr = prev
prev = curr
(PARI) a(n) = (n^2-1+(-1)^(n\2)*(1 + (n % 2)))/2; \\ Michel Marcus, Sep 11 2016
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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