%I
%S 1,1,1,44,211,9136,118799,9894884,368001271,3949758496,
%T 1062959453221,352302017500124,54987975498787651,
%U 11177493084346370144,3145848334837840227961,988952736939184411495964,349477151478120199840810351,141758901275895434356815281984
%N 2nth derivative of sec(x)^cos(x) at x=0.
%C sec(x) = 1/cos(x).
%C The sequence gives only 2nth derivatives because (2n+1)th derivatives are 0.
%t f[x_] := Sec[x]^Cos[x]; Table[Derivative[2*n] [f][0],{n,0,18}]
%Y Cf. A215677.
%K sign
%O 0,4
%A _Michel Lagneau_, Aug 18 2012
