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%I #6 Mar 30 2012 18:57:12
%S 2,3,4,5,6,7,9,10,11,12,13,14,15,16,17,18,19,20,22,23,24,25,26,27,28,
%T 29,30,31,32,33,34,35,36,37,38,39,41,42,43,44,45,46,47,48,49,50,51,52,
%U 53,54,55,56,57,58,59,60,61,62,63,64,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,97,98,99,100,101,102,103,104,105,106
%N Complement of the octagonal numbers.
%F a(n)=n+Floor[1/2+(n/3)^(1/2)]
%e Octagonal numbers: (1,8,21,40,65,...), so that
%e A183220 = (2,3,4,5,6,7,9,10,...,20,22,...39,41...).
%t Table[n+Floor[1/2+(n/3)^(1/2)], {n,100}]
%Y Cf. A000567 (octagonal numbers).
%K nonn
%O 1,1
%A _Clark Kimberling_, Jan 01 2011
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