|
%I #7 Mar 12 2022 13:20:44
%S 1,1,3,16,134,1596,25193,501236,12118038,346373740,11460810227,
%T 431732603292,18269225018646,858920382899880,44455946598501069,
%U 2513531512113074244,154218539815668325502,10209332972405039928876
%N G.f.: 1/(1-x) = Sum_{n>=0} a(n)*x^n/(1+x)^(n^2+n).
%F a(n) = 1 - Sum_{k=0..n-1} a(k)*(-1)^(n-k)*C(k^2+k + n-k-1, n-k) for n>0, with a(0)=1.
%e 1/(1-x) = 1 + x/(1+x)^2 + 3*x^2/(1+x)^6 + 16*x^3/(1+x)^12 + 134*x^4/(1+x)^20 +...
%o (PARI) {a(n)=if(n==0,1,polcoeff(-(1-x)*sum(m=0,n-1,a(m)*x^m/(1+x +x*O(x^n))^(m*(m+1))),n))}
%o (PARI) {a(n)=if(n==0, 1, 1 - sum(j=0, n-1, a(j)*(-1)^(n-j)*binomial(j*(j+1)+n-j-1, n-j)))}
%Y Cf. A182952, A133316, A141761.
%K nonn
%O 0,3
%A _Paul D. Hanna_, Dec 31 2010
|
