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Solutions of A181712(n)=0.
3

%I #2 Mar 30 2012 18:57:11

%S 1,2,5,7,9,10,13,14,15,17,18,22,23,26,28,30,31,34,35,36,39,43,44,47,

%T 48,49,51,52,56,57,60,62,64,65,68,69,70,73,77,78,81,83,85,86,89,90,91,

%U 94,96,98,99,102,103,104,106,107,111,112,115,117,119,120,123,124,125,128

%N Solutions of A181712(n)=0.

%e A181712 begins with 0,0,1,1,0,1,0,1,0,0,1,1,0,0,0,1,0,0,1,1,1,0,0,

%e so that A181713 begins with 1,2,5,7,9,10,13,14,15,17,18,22,23.

%Y Cf. A181712, A181714.

%K nonn

%O 1,2

%A _Clark Kimberling_, Nov 07 2010