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%I #2 Mar 30 2012 17:35:07
%S 113,131,139,173,233,421,953,1013,1021,1051,1583,1747,1901,2099,2423,
%T 2579,2819,2939,3761,3779,3931,4211,4253,4451,4591,5003,5861,5903,
%U 6427,6691,6949,7079,7481,7541,7717,8263,8783,8831,9127,9227,9413,9923,10061
%N First term of four consecutive primes whose average is a prime
%F a(n)=[p(n)+p(n+1)+p(n+2)+p(n+3)]/4 a(n) being a prime
%e a(5)=233 since (233+239+241+251)/4=964/4=241 is a prime.
%Y Cf. A000040, A122535
%K nonn
%O 1,1
%A _Carmine Suriano_, Sep 05 2010
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