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%I #2 Mar 30 2012 17:25:38
%S 1,1,1,1,2,1,1,3,4,1,1,4,6,8,1,1,5,8,12,16,1,1,6,10,16,24,32,1,1,7,12,
%T 20,32,48,64,1,1,8,14,24,40,64,96,128,1,1,9,16,28,48,80,128,192,256,1,
%U 1,10,18,32,56,96,160,256,384,512,1,1,11,20,36,64,112,192,320,512,768
%N Triangle read by rows: antidiagonals of an array formed by sequences of the form a(0)=1, a(1) = (n+1); a(n+1), n>1 = 2*a(n).
%C Row sums = A179744: (1, 2, 4, 9, 20, 43, 90, 185, 376, 759, 1526,...).
%F Form an array with row 0 and column 0 = (1,1,1,...), with (n,1) = (n+1) and
%F a(n+1), n>1, = 2*a(n). Triangle A179743 = antidiagonals of the array.
%e First few rows of the array =
%e .
%e 1,...1,...1,...1,...1,...1,...
%e 1,...2,...4,...8,..16,..32,...
%e 1,...3,...6,..12,..24,..48,...
%e 1,...4,...8,..16,..32,..64,...
%e 1,...5,..10,..20,..40,..80,...
%e ...
%e First few rows of the triangle =
%e .
%e 1;
%e 1, 1;
%e 1, 2, 1;
%e 1, 3, 4, 1;
%e 1, 4, 6, 8, 1;
%e 1, 5, 8, 12, 16, 1;
%e 1, 6, 10, 16, 24, 32, 1;
%e 1, 7, 12, 20, 32, 48, 64, 1;
%e 1, 8, 14, 24, 40, 64, 96, 128, 1;
%e 1, 9, 16, 28, 48, 80, 128, 192, 256, 1;
%e 1, 10, 18, 32, 56, 96, 160, 256, 384, 512, 1;
%e 1, 11, 20, 36, 64, 112, 192, 320, 512, 768, 1024;
%e 1, 12, 22, 40, 72, 128, 244, 384, 640, 1024, 1536, 2048;
%e ...
%Y Cf. A179744
%K nonn,tabl
%O 0,5
%A _Gary W. Adamson_, Jul 25 2010
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