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a(n) = binomial(binomial(binomial(n, 2), 3), 4)/5.
0

%I #11 Sep 07 2018 17:08:27

%S 969,1642914,352470391,25957590316,958073067315,21639468423573,

%T 337726148030733,3946787095970862,36534727415378192,

%U 279109860906071195,1815047255456722287,10290566991057546557,51837653320551263438,235568544405588437778,977816056476957297015,3745739023587032569461,13356862465688668653111

%N a(n) = binomial(binomial(binomial(n, 2), 3), 4)/5.

%F a(n) = binomial( A093566(n+1),4)/5. - _R. J. Mathar_, Dec 08 2010

%F a(n) = n *(n-1) *(n-2) *(n-3) *(n+2) *(n+1) *(n^2-n-4) *(n^6-3*n^5-3*n^4+11*n^3+2*n^2-8*n-96) *(n^4-2*n^3+n^2+8) *(n^6-3*n^5-3*n^4+11*n^3+2*n^2-8*n-144) /637009920. - _R. J. Mathar_, Dec 08 2010

%t Table[Binomial[Binomial[Binomial[n, 2], 3], 4]/5, {n, 4, 30}]

%Y Cf. A093566.

%K nonn

%O 4,1

%A _Roger L. Bagula_, Dec 06 2010