%I #7 Mar 11 2014 01:32:51
%S 1,2,3,2,3,4,5,6,7,8,9,8,9,10,9,8,9,8,9,8,9,8,9,8,7,8,9,8,9,8,9,8,9,8,
%T 9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,10,9,8,9,8,
%U 9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,7,8,9,8,9,8,9,8,9,8,9,8,9,8,9,8,9
%N a(n) = the number of divisors of A175265(n).
%C a(n+1)a(n) = 1, for all n.
%Y A175265
%K nonn
%O 1,2
%A _Leroy Quet_, Mar 18 2010
%E More terms from _Jon E. Schoenfield_, Jun 13 2010
