%I
%S 0,1,1,1,1,1,1,2,2,2,3,3,4,5,5,6,7,9,10,12,14,16,19,22,25,29,34,39,46,
%T 53,62,71,83,96,111,129,149,173,200,232,268,311,360,417,483,560,648,
%U 751,869,1007,1166
%N a(n) = floor( (alpha^nbeta^n)/(alphabeta) ), where alpha=(1 + 3^(1/4))/2 and beta = (1  3^(1/4))/2.
%C The sequence is designed to have alpha as the limiting ratio of a(n+1)/a(n): 1.1580370064762462304...
%t a = (1 + 3^(1/4))/2; b = (1  3^(1/4))/2;
%t f[n_] := Floor[FullSimplify[(a^n  b^n)/(a  b)]]
%t Table[f[n], {n, 0, 50}]
%Y Cf. A174427.
%K nonn,less
%O 0,8
%A _Roger L. Bagula_, Nov 29 2010
