%I #9 Mar 12 2014 16:37:14
%S 1,1,2,3,5,7,10,14,18,23,28,34,40,47,53,61,68,77,85,94,103,113,123,
%T 134,146,158,171,184,198,212,227,241,257,272,289,305,322,339,357,375,
%U 394,414,434,455,476,498,520,543,565,589,612
%N a(n) = a(n-1) + a(n-2) - [a(n-2)/4] - [a(n-3)/2] - [a(n-4)/4].
%C The limiting ratio a(n+1)/a(n) at the 500th iteration is:1.0039960716583698
%F a(n)=a(n-1)+a(n-2)-Floor[a(n-2)/4]-Floor[a(n-3)/2]-Floor[a(n-4)/4]
%t f[-2] = 0; f[-1] = 0; f[0] = 1; f[1] = 1;
%t f[n_] := f[n] = f[n -
%t 1] + f[n - 2] - Floor[f[n - 2]/4] - Floor[f[n - 3]/2] - Floor[f[n - 4]/4]
%t Table[f[n], {n, 0, 50}]
%K nonn
%O 0,3
%A _Roger L. Bagula_, Nov 23 2010