%I #2 Mar 31 2012 10:22:16
%S 2,17,536,67073,33882272,68971196417,563671581328256,
%T 18454625673706995713,2418183685055827278828032,
%U 1267705002132225806674491867137,2658490852011206228820564373456050176
%N a(n)=((2^n+1)^n+(2^n-1)^n)/2
%t Table[((2^x + 1)^x + (2^x - 1)^x)/2, {x, 1, 15}]
%K nonn
%O 1,1
%A _Artur Jasinski_, Feb 01 2010
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