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Triangle read by rows, obtained by dividing A151724 by 6.
10

%I #10 Sep 29 2013 11:33:52

%S 1,1,3,1,3,5,7,1,3,5,9,9,7,13,15,1,3,5,9,9,9,17,25,17,7,13,23,27,19,

%T 31,31,1,3,5,9,9,9,17,25,17,9,17,29,37,33,41,57,33,7,13,23,27,27,43,

%U 67,59,27,31,55,69,49,69,63,1,3,5,9,9,9,17,25,17,9,17,29,37,33,41

%N Triangle read by rows, obtained by dividing A151724 by 6.

%C Row k has 2^k terms.

%C Right border gives the positive terms of A000225. - _Omar E. Pol_, Sep 28 2013

%H N. J. A. Sloane, <a href="/A170898/b170898.txt">Table of n, a(n) for n = 0..1023</a>

%F Equals A170905(n) - 1.

%e Triangle begins:

%e 1;

%e 1,3;

%e 1,3,5,7;

%e 1,3,5,9,9,7,13,15;

%e 1,3,5,9,9,9,17,25,17,7,13,23,27,19,31,31;

%e 1,3,5,9,9,9,17,25,17,9,17,29,37,33,41,57,33,7,13,23,27,27,43,67,59,27,31,55,69,49,69,63;

%e ...

%Y Cf. A169779 (partial sums).

%Y Cf. A139250, A139251, A151723, A151724, A170899.

%K nonn,tabf

%O 0,3

%A _N. J. A. Sloane_, Jan 10 2010