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a(n) = n^4*(n^5 + 1)/2.
1

%I #12 Sep 08 2022 08:45:48

%S 0,1,264,9882,131200,976875,5039496,20178004,67110912,193713525,

%T 500005000,1178981166,2579900544,5302263967,10330542600,19221705000,

%U 34359771136,59293980009,99179697672,161343914050,256000080000

%N a(n) = n^4*(n^5 + 1)/2.

%H Vincenzo Librandi, <a href="/A168196/b168196.txt">Table of n, a(n) for n = 0..405</a>

%F G.f.: x*(1 + 254*x + 7287*x^2 + 44140*x^3 + 78095*x^4 + 44094*x^5 + 7321*x^6 + 248*x^7)/(1 - x)^10. - _Ilya Gutkovskiy_, Jul 15 2016

%t Table[n^4*(n^5 + 1)/2, {n,0,50}] (* _G. C. Greubel_, Jul 15 2016 *)

%o (Magma) [n^4*(n^5+1)/2: n in [0..50]]; // _Vincenzo Librandi_, Apr 25 2011

%K nonn

%O 0,3

%A _N. J. A. Sloane_, Dec 11 2009