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%I #2 Mar 30 2012 18:37:20
%S 1,1,5,27,203,2002,24429,353300,5877619,110140398,2289730547,
%T 52215711142,1294830014579,34674182292270,997028749972868,
%U 30635875305295776,1001785692746640031,34734713374858593257
%N Column 3 of triangle T=A167015: a(n) = T(n+3,3) = [T^(n+3)](n-1,0) for n>0 with a(0)=1.
%C In triangle T=A167015, row n of T equals the initial n terms in column 0 of matrix power T^n, reversed and with an appended '1'.
%o (PARI) {A167015(n,k)=local(M,N);if(n==k|n==k+1,1,if(n==k+2,k+2, N=matrix(n,n,r,c,if(r>=c,A167015(r-1,c-1))); M=matrix(n+1,n+1,r,c,if(r>=c,if(r<=n,N[r,c],(N^n)[n-k,1])));M[n+1,k+1]))}
%o (PARI) {a(n)=A167015(n+3,3)}
%Y Cf. A167015, A167016, A167017, A167018.
%K nonn
%O 0,3
%A _Paul D. Hanna_, Oct 27 2009
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