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A165714 Let the prime factorization of m be m = product p(m,k)^b(m,k), where p(m,j)<p(m,j+1) for all j, the p's are the distinct primes dividing m, and each b is a positive integer. Then a(n) = product_k {p(A165713(n), k)^b(n,k)}. 1

%I

%S 3,2,25,7,10,2,27,121,6,13,28,2,15,6,83521,19,50,23,63,22,6,5,104,9,

%T 14,24389,99,31,42,2,69343957,34,35,6,1444,41,39,10,88,43,30,47,45,92,

%U 6,7,80,2809,867,26,12,59,6655,14,513,58,62,61,132,2,21,325,90458382169,34

%N Let the prime factorization of m be m = product p(m,k)^b(m,k), where p(m,j)<p(m,j+1) for all j, the p's are the distinct primes dividing m, and each b is a positive integer. Then a(n) = product_k {p(A165713(n), k)^b(n,k)}.

%C A165713(n) = the smallest integer > n that is divisible by exactly the same number of distinct primes as n is.

%e 12 = 2^2 * 3^1, which is divisible by 2 distinct primes. The next larger integer divisible by exactly 2 distinct primes is 14 = 2^1 * 7^1. Taking the primes from the factorization of 14 and the exponents from the factorization of 12, we have a(12) = 2^2 * 7^1 = 28.

%Y Cf. A165713, A165715.

%K nonn

%O 2,1

%A _Leroy Quet_, Sep 24 2009

%E Extended by _Ray Chandler_, Mar 12 2010

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Last modified December 4 17:50 EST 2021. Contains 349526 sequences. (Running on oeis4.)