%I #7 Mar 11 2014 01:32:46
%S 1,2,6,12,44,44,236,472,2520,10712,10712,10712,10712,10712,125400,
%T 250800,2347952,19125168,19125168,19125168,354669488,354669488,
%U 6260249520,6260249520,109339464624,109339464624,109339464624
%N a(1)=1. a(n) = the smallest positive integer that, when written in binary, contains both binary a(n1) and binary n as (possibly overlapping) substrings.
%e a(6) = 44, which is 101100 in binary. a(7) therefore contains both 101100 and the binary representation of 7, which is 111, as substrings when a(7) is written in binary. So a(7) = 236, which is 11101100 in binary. (Both substrings share a single digit of 1.)
%Y Cf. A056744.
%K base,nonn
%O 1,2
%A _Leroy Quet_, Aug 28 2009
%E Extended by _Ray Chandler_, Mar 14 2010
