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%I #7 Sep 16 2018 04:40:28
%S 3,6,15,20,21,33,35,39,42,63,66,71,72,80,81,92,110,111,117,119,126,
%T 135,150,155,156,158,159,164,167,174,176,197,201,203,204,210,213,215,
%U 225,237,242,245,248,249,260,264,279,303,317,320,323,326,329,330,333,335
%N Numbers k such that T(k) is an anagram of a pronic number.
%C 21 is in the sequence because T(21) = 21*22/2 = 231 and 231 is an anagram of 132 = 11 * 12.
%Y Cf. A002378.
%K nonn,base
%O 1,1
%A _Claudio Meller_, Jul 01 2009