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%I #10 Sep 16 2018 04:40:24
%S 1,22,24,25,34,36,43,48,51,54,55,57,58,61,64,67,69,72,73,75,82,85,87,
%T 88,91,93,97,102,105,106,108,109,111,117,118,124,127,129,133,135,136,
%U 139,141,145,147,148,151,153,154,159,166,168,169,172,174,175,177,183,184
%N Numbers k such that k^3 is an anagram of a triangular number.
%C 24 is in the sequence because 24^3 = 13824 and 13824 is an anagram of 41328 = 287*288/2 = T(287).
%H Chai Wah Wu, <a href="/A162334/b162334.txt">Table of n, a(n) for n = 1..1000</a>
%Y Cf. A000217.
%K nonn,base
%O 1,2
%A _Claudio Meller_, Jul 01 2009