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Omit first term of A160458 and divide by 5.
2

%I #14 Jan 04 2019 04:08:39

%S 2,13,66,286,1102,3879,12688,39050,114114,318863,856654,2222688,

%T 5589916,13668072,32576016,75845402,172830788,386088741,846744800,

%U 1825447086,3872819904,8094022001,16679126516,33916289400,68106769602,135148379654,265177195950

%N Omit first term of A160458 and divide by 5.

%H Seiichi Manyama, <a href="/A160459/b160459.txt">Table of n, a(n) for n = 1..1000</a>

%H Watson, G. N., <a href="http://www.digizeitschriften.de/dms/resolveppn/?PID=GDZPPN002174499">Ramanujans Vermutung ueber Zerfaellungsanzahlen.</a> J. Reine Angew. Math. (Crelle), 179 (1938), 97-128. See the expression C^2/B^10.

%F a(n) = 1/5 * A160458(n) = 1/5 * Sum_{k=0..n} A277212(k)*A277212(n-k) = 2 * A277974(n) + 5 * Sum_{k=1..n-1} A277974(k)*A277974(n-k). - _Seiichi Manyama_, Nov 27 2016

%o (PARI) x='x+O('x^66); v=Vec((eta(x^5)/eta(x)^5)^2); vector(#v-1,j,v[j+1]/5) \\ _Joerg Arndt_, Nov 27 2016~

%Y Cf. A160458, A277212, A277974.

%K nonn

%O 1,1

%A _N. J. A. Sloane_, Nov 13 2009