OFFSET
1,1
COMMENTS
The identity (14641*n^2 - 24684*n + 10405)^2 - (121*n^2 - 204*n + 86)*(1331*n - 1122)^2 = 1 can be written as A157442(n)^2 - A157440(n)*a(n)^2 = 1. - Vincenzo Librandi, Jan 29 2012
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..10000
Vincenzo Librandi, X^2-AY^2=1
Index entries for linear recurrences with constant coefficients, signature (2,-1).
FORMULA
G.f.: x*(209 + 1122*x)/(x-1)^2. - Vincenzo Librandi, Jan 29 2012
a(n) = 2*a(n-1) - a(n-2). - Vincenzo Librandi, Jan 29 2012
MATHEMATICA
LinearRecurrence[{2, -1}, {209, 1540}, 50] (* Vincenzo Librandi, Jan 29 2012 *)
PROG
(Magma) I:=[209, 1540]; [n le 2 select I[n] else 2*Self(n-1)-Self(n-2): n in [1..50]]; // Vincenzo Librandi, Jan 29 2012
(PARI) for(n=1, 40, print1(1331*n - 1122", ")); \\ Vincenzo Librandi, Jan 29 2012
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Mar 01 2009
STATUS
approved