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%I #15 Sep 10 2023 21:55:28
%S 53,279,3973,28721,325127,6101578,44699964,345060753
%N Minimum power to which 2 must be raised so that the first n digits of the result are the digits of A155699(n).
%e The powers of 2 having at least 2 digits are 16, 32, 64, 128, 256, ...; discarding all but their first 2 digits yields the sequence 16, 32, 64, 12, 25, ..., in which all 90 of the possible 2-digit numbers (10 through 99) eventually appear; the last to appear is 97, which appears at 2^279 = 9.713...*10^83), so a(2) = 279.
%Y Cf. A000079, A155699.
%K nonn,base,more
%O 1,1
%A _Jon E. Schoenfield_, Jan 25 2009
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