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%I #31 Jan 22 2021 07:09:46
%S 1,0,2,1,6,5,1,2,4,7,5,3,1,9,8,1,3,6,6,4,1,1,0,2,8,1,9,2,6,0,7,3,2,3,
%T 8,6,9,7,5,6,2,2,1,5,9,2,8,9,1,5,3,6,5,4,0,3,5,5,9,0,7,1,1,5,6,7,3,3,
%U 6,9,3,8,8,9,7,8,0,9,7,5,9,5,5,1,3,0,3,6,2,4,6,5,5,8,8,9,5,0,4,4
%N Decimal expansion of 2*log(5/3) used in BBP Pi formula.
%C BBP formula for Pi = 4*A145963 - (1/2)*A145960 - (1/2)*(A145961-A145962).
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/BBPFormula.html">BBP Formula</a>
%H <a href="/index/Tra#transcendental">Index entries for transcendental numbers</a>
%F Equals 2*log(5/3) = 2*(log(5)-log(3)) = 2*(A016628 - A002391) = log(25/9) = 4*arctanh(1/4).
%F Equals Hypergeometric2F1(1, 1/2, 3/2, 1/16).
%F Equals Sum_{k>=0} (1/16)^k*(1/(2k+1)).
%e 1.021651247531981366411...
%t First[RealDigits[2 Log[5/3], 10, 100]]
%o (PARI) 2*log(5/3) \\ _Michel Marcus_, Apr 05 2015
%Y Cf. A000796, A145961, A145962, A145963.
%K cons,nonn
%O 1,3
%A _Artur Jasinski_, Oct 25 2008
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