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 A145756 a(n) = ((2^prime(n+2)-2)/prime(n+2))/3, where n >= 1 0

%I #3 Oct 12 2013 15:30:56

%S 2,6,62,210,2570,9198,121574,6170930,23091222,1238188770,17878237850,

%T 68186767614,998138215286,56649051916610,3256840408493918,

%U 12600235023025650,734198769102867726,11085367330679918342

%N a(n) = ((2^prime(n+2)-2)/prime(n+2))/3, where n >= 1

%e For n = 1, a(1) = ((2^prime(1+2)-2)/prime(1+2))/3 = ((2^prime(3)-2)/prime(3))/3 = ((2^5-2)/5)/3 = 30/5/3 = 2

%Y Equals A064535/3

%K nonn

%O 1,1

%A _Vassilis Papadimitriou_, Oct 17 2008

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Last modified June 25 15:24 EDT 2024. Contains 373705 sequences. (Running on oeis4.)