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%I #6 Apr 18 2013 11:27:42
%S 1,1,1,0,1,2,1,0,2,3,1,1,0,3,6,0,1,2,0,6,11,1,0,2,3,0,11,20,1,1,0,3,6,
%T 0,20,37,0,1,2,0,6,11,0,37,68,1,0,2,3,0,11,20,0,68,125
%N Eigentriangle, row sums = A001590
%C Row sums = A001590 starting (1, 2, 3, 6, 11, 20, 37,...).
%C Sum of n-th row terms = rightmost term of next row.
%F Let M = an infinite lower triangular matrix with (1, 1, 0, 1, 1, 0,...) in every column and X = a diagonalized matrix of A001590: (1, 1, 2, 3, 6, 11, 20, 37,...), (i.e. A001590 starting with offset 3 as a diagonal prefaced with a 1; and the rest zeros). Triangle A145579 = M * X.
%e First few rows of the triangle =
%e 1;
%e 1, 1;
%e 0, 1, 2;
%e 1, 0, 2, 3;
%e 1, 1, 0, 3, 6;
%e 0, 1, 2, 0, 6, 11;
%e 1, 0, 2, 3, 0, 11, 20;
%e 1, 1, 0, 3, 6, 0, 20, 37;
%e 0, 1, 2, 0, 6, 11, 0, 37, 68;
%e 1, 0, 2, 3, 0, 11, 20, 0, 68, 125;
%e ...
%e Row 7 = (1, 1, 0, 3, 6) = termwise products of (1, 1, 0, 1, 1) and (1, 1, 2, 3, 6).
%Y A001590
%K nonn,tabl
%O 3,6
%A _Gary W. Adamson_, Oct 13 2008
%E Alignment of example rows and unintentional concatenation of values fixed by Charles J. Daniels (chajadan(AT)gmail.com), Dec 05 2009
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