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A145086 Row 0 of square table A145085. 6

%I #4 Mar 30 2012 18:37:15

%S 1,1,2,7,39,322,3723,57577,1147188,28557909,866222535,31362744620,

%T 1332663774173,65529062871157,3684878011841690,234605021214637355,

%U 16766728751635089083,1335146927494755758530,117695398260381996143695

%N Row 0 of square table A145085.

%C Let S(n,x) be the e.g.f. of row n of square table A145085, then the e.g.f.s satisfy: S(n,x) = exp( Integral S(n+1,x)^(n+1) dx ) for n>=0.

%H Paul D. Hanna, <a href="/A145086/b145086.txt">Table of n, a(n) for n=0..60</a>

%F E.g.f.: A(x) = exp( Integral R(1,x) dx ) where R(1,x) is the e.g.f. of A145081, which is row 1 of square table A145080.

%o (PARI) {a(n)=local(A=vector(n+2,j,1+j*x)); for(i=0,n+1,for(j=0,n,m=n+1-j;A[m]=exp(m*intformal(A[m+1]+x*O(x^n))))); n!*polcoeff(exp(intformal(A[1])),n,x)}

%o (PARI) {a(n)=local(A=vector(n+2,j,1+j*x)); for(i=0,n+1,for(j=0,n,m=n+1-j;A[m]=exp(intformal(A[m+1]^(m+1)+x*O(x^n))))); n!*polcoeff(exp(intformal(A[1])),n,x)}

%Y Cf. A145085, A145087, A145088, A145089; A145080, A145081.

%K nonn

%O 0,3

%A _Paul D. Hanna_, Oct 01 2008

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