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%I #4 Nov 17 2019 01:05:36
%S 2,2,1,2,1,2,2,1,1,3,2,1,1,2,4,2,1,1,2,2,6,2,1,1,2,2,2,9,2,1,1,2,2,2,
%T 2,14,2,1,1,2,2,2,2,2,22,2,1,1,2,2,2,2,2,2,35,2,1,1,2,2,2,2,2,2,2,56
%N A triangle sequence designed as a step function around the determinants: a(n)=A000045(n); t(n,m)=If[m == 0 || m == 1, 2 - m, If[ m < n, Ceiling[(a(m) - 1)/a(n) + 1], a(n) + 1]].
%C Row sums: {2, 3, 5, 7, 10, 14, 19, 26, 36, 51, 74}.
%F a(n)=A000045(n); t(n,m)=If[m == 0 || m == 1, 2 - m, If[ m < n, Ceiling[(a(m) - 1)/a(n) + 1], a(n) + 1]].
%e {2},
%e {2, 1},
%e {2, 1, 2},
%e {2, 1, 1, 3},
%e {2, 1, 1, 2, 4},
%e {2, 1, 1, 2, 2, 6},
%e {2, 1, 1, 2, 2, 2, 9},
%e {2, 1, 1, 2, 2, 2, 2, 14},
%e {2, 1, 1, 2, 2, 2, 2, 2, 22},
%e {2, 1, 1, 2, 2, 2, 2, 2, 2, 35},
%e {2, 1, 1, 2, 2, 2, 2, 2, 2, 2, 56}
%t Clear[a, b, t, n, m]; a[n_] := Fibonacci[n]; t[n_, m_] := If[m == 0 || m == 1, 2 - m, If[ m < n, Ceiling[(a[m] - 1)/a[n] + 1], a[n] + 1]]; Table[Table[t[n, m], {m, 0, n}], {n, 0, 10}]; Flatten[%]
%Y Cf. A000045.
%K nonn,uned
%O 1,1
%A _Roger L. Bagula_ and _Gary W. Adamson_, Oct 08 2008
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