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Last digit of A135266(n).
0

%I #10 Dec 12 2023 08:29:23

%S 0,1,5,9,0,2,6,9,9,1,6,0,0,1,5,9,0,2,6,9,9,1,6,0,0,1,5,9,0,2,6,9,9,1,

%T 6,0,0,1,5,9,0,2,6,9,9,1,6,0,0,1,5,9,0,2,6,9,9,1,6,0,0,1,5,9,0,2,6,9,

%U 9,1,6,0,0,1,5,9,0,2,6,9,9,1,6,0,0,1,5,9,0,2,6,9,9,1,6,0,0,1,5,9,0,2

%N Last digit of A135266(n).

%F Period 12: a(n+12)=a(n).

%F Sums of periodic trisections: a(3n)+a(3n+3)+a(3n+6)+a(3n+9) = a(3n+1)+a(3n+4)+a(3n+7)+a(3n+10) = a(3n+2)+a(3n+5)+a(3n+8)+a(3n+11) = 16.

%F G.f.: x(6x^7-5x^6+8x^5+6x^4-8x^3+4x^2+4x+1)/((1-x)(1+x)(x^2+1)(x^2-x+1)(x^4-x^2+1)). - _R. J. Mathar_, Dec 02 2008

%K nonn,base

%O 0,3

%A _Paul Curtz_, Sep 30 2008

%E Edited by _R. J. Mathar_, Dec 02 2008