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A143778
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Eigentriangle of A001263, the Narayana triangle.
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1
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1, 1, 1, 1, 3, 2, 1, 6, 12, 6, 1, 10, 40, 60, 25, 1, 15, 100, 300, 375, 136, 1, 21, 210, 1050, 2625, 2856, 927, 1, 18, 392, 2940, 12250, 26656, 25956, 7690, 1, 36, 672, 7056, 44100, 15993, 311472, 276840, 75913
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OFFSET
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0,5
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COMMENTS
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The Narayana triangle begins:
1;
1, 1;
1, 3, 1;
1, 6, 6, 1;
1, 10, 20, 10, 1;
...
An eigentriangle of T is generated by taking the termwise product of (n-1)-th row terms of triangle T (in this case the Narayana triangle A001263); and the eigensequence of T = A102812 = (1, 1, 2, 6, 25, 136, 927,...).
Sum of n-th row terms of triangle A143778 = rightmost term of (n+1)-th row.
Right border of the triangle = the eigensequence of T.
Row sums of the triangle = the eigensequence of T shifted one place to the left: (1, 2, 6, 25, 136,...)
(A102812 * 0^(n-k)) = an infinite lower triangular matrix with A102812 as the main diagonal and the rest zeros.
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LINKS
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FORMULA
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Apparently for k<n, a(n,k)= binomial(n+1,k+1)*n!/(n+1-k)!. - Tom Copeland, Oct 08 2014
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EXAMPLE
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Triangle begins:
1;
1, 1;
1, 3, 2;
1, 6, 12, 6;
1, 10, 40, 60, 25;
1, 15, 100, 300, 375, 136;
1, 21, 210, 1050, 2625, 2856, 927;
...
Row 3 = (1, 6, 12, 6) = (1*1, 6*1, 6*2, 1*6) = termwise product of row 3 of the Narayana triangle: (1, 6, 6, 1) and the first 4 terms of the eigensequence of the Narayana triangle = (1, 1, 2, 6).
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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