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Consider pairs m,n such that 1/(UnitaryPhi(m))^(1/2) = 1/(UnitaryPhi(n))^(1/2) = k^(1/2)*(1/m^(1/2)-1/n^(1/2)), n<m; sequence gives values of n.
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%I #4 Apr 21 2024 22:12:29

%S 4920320,12681574400,20926651432960000

%N Consider pairs m,n such that 1/(UnitaryPhi(m))^(1/2) = 1/(UnitaryPhi(n))^(1/2) = k^(1/2)*(1/m^(1/2)-1/n^(1/2)), n<m; sequence gives values of n.

%Y Cf. A143686, A143688.

%K nonn,bref

%O 1,1

%A _Yasutoshi Kohmoto_, Nov 13 2008, Nov 21 2008