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%I #4 Mar 30 2012 18:51:58
%S 1,1,1,1,2,1,1,2,1,1,1,4,1,2,1,1,4,1,2,1,1,1,4,1,1,1,2,1,1,4,1,1,1,2,
%T 1,1,1,8,1,2,1,4,1,2,1,1,8,1,2,1,4,1,2,1,1,1,8,1,1,1,4,1,2,1,2,1,1,8,
%U 1,1,1,4,1,2,1,2,1,1,1,8,1,2,1,2,1,2,1,4,1,2,1,1,8,1,2,1,2,1,2,1,4,1,2,1,1
%N Denominators of the inverse triangle to that described in A133135.
%C The inverse of the triangle of fractions starts
%C 1;
%C -1, 1;
%C 1, -3/2, 1;
%C -1, 3/2,-2, 1;
%C 1, -5/4, 2, -5/2, 1;
%C -1, 5/4 -1, 5/2, -3, 1;
%C 1, -7/4, 1, 0, 3, -7/2, 1;
%C -1, 7/4,-4, 0, 2, 7/2,-4, 1;
%C 1, 3/8, 4,-21/2, -2, 21/4, 4,-9/2, 1;
%C -1, -3/8,13, 21/2,-26,-21/4,10, 9/2,-5, 1;
%C to yield the triangle of denominators
%C 1;
%C 1,1;
%C 1,2,1;
%C 1,2,1,1;
%C 1,4,1,2,1;
%C 1,4,1,2,1,1;
%C 1,4,1,1,1,2,1;
%C 1,4,1,1,1,2,1,1;
%C 1,8,1,2,1,4,1,2,1;
%C 1,8,1,2,1,4,1,2,1,1;
%C 1,8,1,1,1,4,1,2,1,2,1;
%C 1,8,1,1,1,4,1,2,1,2,1,1;
%C Number pairs show up if reading this along diagonals or columns.
%Y Cf. A133135, A140216, A000079.
%K nonn,frac,tabl
%O 0,5
%A _Paul Curtz_, Jun 22 2008
%E Extended by _R. J. Mathar_, Aug 02 2008
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