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%I #2 Mar 30 2012 18:51:58
%S 1,1,2,5,9,28,48,165,275,1001,1638,6188
%N Last term of A139687(n) with a fourth leading 1 = 1, 1, 1, 1, 2, 2, 1, 3, 5, 5 rows.
%C Based on sequences identical to their p-th differences.
%F Odd rows are 1; 1, 2, 2; 1, 3, 6, 9, 9; 1, 4, 10, 20, 34, 48, 48; 1, 5, 15, 35, 70, 125, 200, 275, 275; 1, 6, 21, 56, 126, 252, 461, 780, 1209, 1638, 1638; with respective sums second bisection a(2n+1)= 1, 5, 28, 165, 1001, 6188 = A025174(n+1)?
%Y Cf. A094600.
%K nonn,uned
%O 0,3
%A _Paul Curtz_, Jun 14 2008
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