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a(n+1)=sopfr(3a(n)+1), with sopfr=A001414. Finishes with 17 (fixed point).
3

%I #6 Dec 19 2022 18:04:13

%S 1,4,13,11,19,31,49,41,35,55,85,16,14,43,20,61,29,17

%N a(n+1)=sopfr(3a(n)+1), with sopfr=A001414. Finishes with 17 (fixed point).

%C In the class of recurrence sequences a(n+1)=sopfr(C*a(n)+D), with C=3, D=1.

%F a(n+1)=A001414(3*a(n)+1)

%t See A136136

%t Most[FixedPointList[Total[Times@@@FactorInteger[3#+1]]&,1]] (* _Harvey P. Dale_, Dec 19 2022 *)

%K fini,nonn

%O 1,2

%A _Carlos Alves_, Dec 16 2007