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%I #8 Apr 09 2014 10:17:00
%S 1,2,3,2,5,6,7,8,3,10,11,6,13,14,15,8,17,6,19,8,21,22,23,24,5,26,27,8,
%T 29,30,31,8,33,34,35,24,37,38,39,40,41,36,43,8,15,46,47,24,7,10,51,8,
%U 53,36,55,56,57,58,59,24,61,62,21,64,65,36,67,8,69,70,71,24,73,74,15,8,77,36,79,40
%N Multiply the positive divisors n in order (starting at 1). a(n) is the largest such partial product that is <= n.
%e The positive divisors of 12 are 1,2,3,4,6,12. Checking the partial products: 1=1, 1*2=2, 1*2*3=6, 1*2*3*4=24, 1*2*3*4*6 = 144, 1*2*3*4*6*12 = 1728. 6 is the largest such product that is <= 12. So a(12) = 6.
%o (PARI) for(n=1,80,d=divisors(n);L=numdiv(n);T=1;i=1;while(i<=L&&T*d[i]<=n,T*=d[i];i++);print1(T","))
%Y Cf. A135874.
%K nonn
%O 1,2
%A _Leroy Quet_, Dec 03 2007
%E More terms from _Robert Gerbicz_, Nov 26 2010
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