%I #13 Sep 08 2022 08:45:31
%S 1,6,63,873,8325,5994,46953,817182,2903094,46581471,628884972,
%T 2389033773,83620243341,640064127105,362674830483,8982898406712,
%U 27204409379835,10972654622361,66143772953856,631327736268693,8512167146697873,83278108820037015,90222029256866994
%N Multiply previous term by 6 and reverse.
%H Andrew Howroyd, <a href="/A132078/b132078.txt">Table of n, a(n) for n = 1..200</a>
%H Vaclav Kotesovec, <a href="/A132078/a132078.jpg">Plot of a(n)^(1/n) for n = 1..10000</a>
%F a(n) = reverse(6 * a(n-1)) where a(1) = 1.
%e a(4) = reverse(6 * a(3)) = reverse(6 * reverse(6 * a(2))) = reverse(6 * reverse( 6 * reverse(6 * a(1)))) = reverse(6 * reverse(6 * reverse(6))) = reverse(6 * 63) = 873.
%o (Magma) f:=func<n|Seqint(Reverse(Intseq(6*n)))>; a:=[1]; for n in [2..25] do Append(~a,f(a[n-1])); end for; a; // _Marius A. Burtea_, Jan 03 2020
%Y Cf. A036447 (*2), A163632 (*3), A132064 (*4), A045539 (*5), A132114 (*7), A132113 (*8), A133361 (*9).
%K base,nonn
%O 1,2
%A Rachit Agrawal (rachit_agrawal(AT)daiict.ac.in), Oct 30 2007
%E Name clarified and terms a(16) and beyond from _Andrew Howroyd_, Jan 02 2020
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