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%I #2 Mar 30 2012 17:34:21
%S 1,4,8,11,4,8,11,1,8,11,1,4,11,3,6,10,4,8,11,1,8,11,1,4,11,3,6,10,1,4,
%T 8,11,8,11,1,4,11,3,6,10,1,4,8,11,4,8,11,1,11,3,6,10,3,6,10,11,6,10,1,
%U 5,10,11,3,6,4,8,11,1,8,11,1,4,11,3,6,10,1,4,8,11,8,11,1,4,11,3,6,10,1,4
%N Jazz chord substitution: Aminor,Cminor,DMajor,GMajor Uses a start vector based on these: {1, 4, 6, 11}.
%C Actually a little more complex than most CGF chord type Jazz.
%F 1-> {1, 4, 8, 11}; 2-> {2, 4, 7, 11}; 3-> {3, 6, 10, 11}; 4->{4, 8, 11, 1}; 5-> {5, 6, 10, 1}; 6-> {6, 10, 1, 5}; 7-> {7, 11, 12, 4}; 8->{8, 11, 1, 4}; 9-> {9, 1, 4, 8}; 10-> {10, 11, 3, 6}; 11->{11, 3, 6, 10}; 12->{12, 4, 7, 11};
%t Clear[s] s[1] = {1, 4, 8, 11}; s[2] = {2, 4, 7, 11}; s[3] = {3, 6, 10, 11}; s[4] = {4, 8, 11, 1}; s[5] = {5, 6, 10, 1}; s[6] = {6, 10, 1, 5}; s[7] = {7, 11, 12, 4}; s[8] = {8, 11, 1, 4}; s[9] = {9, 1, 4, 8}; s[ 10] = {10, 11, 3, 6}; s[11] = {11, 3, 6, 10}; s[12] = {12, 4, 7, 11}; t[a_] := Flatten[s /@ a]; p[0] = {1, 4, 6, 11}; p[1] = t[p[0]]; p[n_] := t[p[n - 1]]; p[3]
%K nonn,uned
%O 1,2
%A _Roger L. Bagula_, Oct 21 2007
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