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A131090 First differences of A131666. 4

%I #12 Jan 15 2016 18:28:08

%S 0,1,0,1,1,4,7,15,28,57,113,228,455,911,1820,3641,7281,14564,29127,

%T 58255,116508,233017,466033,932068,1864135,3728271,7456540,14913081,

%U 29826161,59652324,119304647,238609295,477218588,954437177,1908874353

%N First differences of A131666.

%C The first differences b(n)=a(n+1)-a(n) obey the recurrence b(n+1)-2b(n) = (-3,3,-2,3,-3,2), continued with period 6.

%C The 2nd differences c(n)=b(n+1)-b(n) obey the recurrence c(n+1)-2c(n) = (6,-5,5,-6,5,-5), periodically continued with period 6.

%C The hexaperiodic coefficients in these recurrences for A113405, A131666 and their higher order differences define a table,

%C 0, 0, 1, 0, 0, -1 <- A113405

%C 0, 1, -1, 0, -1, 1 <- A131666

%C 1, -2, 1, -1, 2, -1 <- a(n)

%C -3, 3, -2, 3, -3, 2 <- b(n)

%C 6, -5, 5, -6, 5, -5 <- c(n)

%C -11,10,-11, 11,-10, 11

%C 21,-21,22,-21, 21,-22

%C ...

%C in which the first three columns are A024495, A131708 and A024493, multiplied by a checkerboard pattern of signs.

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (2,0,-1,2).

%F a(n) = A131666(n+1)-A131666(n).

%F a(n+1)-2a(n) = A131556(n), a sequence with period length 6.

%F G.f.: -(x-1)^2*x / ((x+1)*(2*x-1)*(x^2-x+1)). - _Colin Barker_, Mar 04 2013

%t LinearRecurrence[{2,0,-1,2},{0,1,0,1},40] (* _Harvey P. Dale_, Jan 15 2016 *)

%K easy,nonn

%O 0,6

%A _Paul Curtz_, Sep 24 2007

%E Edited by _R. J. Mathar_, Jun 28 2008

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Last modified April 19 23:15 EDT 2024. Contains 371798 sequences. (Running on oeis4.)