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%I #4 Aug 06 2016 16:34:33
%S 1,2,3,4,5,6,7,8,9,10,12,15,19,24,29,34,39,44,49,54,59,64,69,74,79,84,
%T 89,94,99,104,110,118,128,139,151,165,180,196,213,231,250,269,288,307,
%U 326,345,364,383,402,421,441,462
%N a(1) = 1; a(n) = a(n-1) + (number of times the digit 1 has appeared in the sequence so far).
%p A130224 := proc(n)
%p option remember;
%p if n = 1 then
%p 1;
%p else
%p a := procname(n-1) ;
%p for j from 1 to n-1 do
%p for d in convert(procname(j),base,10) do
%p if d = 1 then
%p a := a+1 ;
%p end if;
%p end do:
%p end do:
%p a ;
%p end if;
%p end proc:
%p seq(A130224(n),n=1..52) ; # _R. J. Mathar_, Aug 06 2016
%K base,easy,nonn
%O 1,2
%A _Eric Angelini_, Aug 05 2007
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