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Moebius transform of A128229.
0

%I #2 Mar 30 2012 17:25:19

%S 1,0,1,-1,2,1,-1,-1,3,1,-1,0,0,4,1,0,-3,-1,0,5,1,-1,0,0,0,0,6,1,0,0,

%T -3,-1,0,0,7,1,0,-2,-1,0,0,0,0,8,1,0,-1,0,-4,-1,0,0,0,9,1

%N Moebius transform of A128229.

%C Row sums = phi(n), A000010: (1, 1, 2, 2, 4, 2, 6,...). A128259 = inverse Moebius transform of A128229.

%F A054525 * A128229

%e First few rows of the triangle are:

%e 1;

%e 0, 1;

%e -1, 2, 1;

%e -1, -1, 3, 1;

%e -1, 0, 0, 4, 1;

%e 0, -3, -1, 0, 5, 1;

%e ...

%Y Cf. A128259, A128229, A054525, A000010.

%K tabl,sign

%O 1,5

%A _Gary W. Adamson_, Feb 21 2007