%I #8 Nov 22 2023 22:39:11
%S 1,2,4,10,23,59,149,387,1000,2607,6799,17770,46457,121542,318044,
%T 832427,2178919,5703887,14931949,39090776,102338336,267921095,
%U 701419679,1836329673,4807555633,12586315482
%N A bisection of the row sums of the inverse of the triangle A(n,k) = 1/F(n+1) if k <= n <= 2k, 0 otherwise.
%F a(n) = A127712(2n+1). Note that A127712(2n) = F(2n-1).
%Y Cf. A127712.
%K nonn
%O 0,2
%A _Paul Barry_, Jan 24 2007