%I #5 Sep 29 2018 18:44:19
%S 1,1,1,2,2,4,5,10,13,23,34,59,89,149,233,387,610,1000,1597,2607,4181,
%T 6799,10946,17770,28657,46457,75025,121542,196418,318044,514229,
%U 832427,1346269,2178919,3524578,5703887,9227465,14931949,24157817,39090776
%N Row sums of the inverse of the triangle A(n,k) = 1/F(n+1) if k <= n <= 2k, 0 otherwise.
%C Row sums of A127711. a(2n) = F(2n1). a(2n+1) = A127713(n).
%K nonn
%O 0,4
%A _Paul Barry_, Jan 24 2007
