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A127363 a(n) = Sum_{k=0..n} C(n,floor(k/2))*(-4)^(n-k). 4

%I #12 Aug 23 2022 14:51:27

%S 1,-3,14,-57,246,-1038,4424,-18777,79846,-339258,1442004,-6128202,

%T 26045436,-110691948,470442924,-1999378137,8497365126,-36113785698,

%U 153483619604,-652305322542,2772297736276,-11782265148228,50074627320864,-212817165231882,904472953925596

%N a(n) = Sum_{k=0..n} C(n,floor(k/2))*(-4)^(n-k).

%C Hankel transform is 5^n. In general, for r>=0, the sequence given by Sum_{k=0..n} C(n,floor(k/2))*(-r)^(n-k) has Hankel transform (r+1)^n. The sequence is the image of the sequence with g.f. (1+x)/(1+4x) under the Chebyshev mapping g(x)->(1/sqrt(1-4x^2))g(xc(x^2)), where c(x) is the g.f. of the Catalan numbers A000108.

%H Vincenzo Librandi, <a href="/A127363/b127363.txt">Table of n, a(n) for n = 0..200</a>

%F G.f.: (1/sqrt(1-4x^2))(1+x*c(x^2))/(1+4*x*c(x^2)).

%F Conjecture: 4*n*a(n) +(17*n-8)*a(n-1) +2*(-8*n-1)*a(n-2) +68*(-n+2)*a(n-3)=0. - _R. J. Mathar_, Nov 24 2012

%F a(n) ~ (-1)^n * 3 * 17^n / 4^(n+1). - _Vaclav Kotesovec_, Feb 12 2014

%t CoefficientList[Series[1/Sqrt[1-4*x^2] * (1+x*(1-Sqrt[1-4*x^2]) / (2*x^2)) / (1+4*x*(1-Sqrt[1-4*x^2])/(2*x^2)), {x, 0, 20}], x] (* _Vaclav Kotesovec_, Feb 12 2014 *)

%Y Cf. A000108.

%K easy,sign

%O 0,2

%A _Paul Barry_, Jan 11 2007

%E More terms from _Vincenzo Librandi_, Feb 13 2014

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Last modified April 24 00:30 EDT 2024. Contains 371917 sequences. (Running on oeis4.)